Which Inequality In Standard Form Represents The Shaded Region - Web for example, an inequality of the form π¦ β₯ π π₯ + π is presented by a solid line, where the shaded region will be above the straight line π¦ = π π₯ + π, whereas the inequality π¦ > π π₯ + π has the same shaded region but the boundary is presented by a dashed line. If you doubt that, try substituting the x and y coordinates of points a and b into the inequalityβyouβll see that they work. Every ordered pair in the shaded area below the line is a solution to y < 2x+5 y < 2 x + 5, as all of the points below the line will make the inequality true. In this case, we can see that the origin ( 0 , 0 ) β is a solution because it is in the shaded part, but the point ( 4 , 4 ) β is not a solution because it is outside of the shaded part. The graph shows the inequality \(y\geq 2xβ1\). Web which inequality in standard form represents the shaded region? Thereβs just one step to solve this. Web the shaded region for the inequality is below the line. Web the dashed line is y= 2x+5 y = 2 x + 5. Web the shaded region shows the solution of the inequality \(y>2xβ1\).
If you doubt that, try substituting the x and y coordinates of points a and b into the inequalityβyouβll see that they work. Since the boundary line is graphed with a solid line, the inequality includes the equal sign. The graph shows the inequality \(y\geq 2xβ1\). Web which inequality in standard form represents the shaded region? How to solve a system of linear inequalities by graphing. Web the dashed line is y= 2x+5 y = 2 x + 5. Web for example, an inequality of the form π¦ β₯ π π₯ + π is presented by a solid line, where the shaded region will be above the straight line π¦ = π π₯ + π, whereas the inequality π¦ > π π₯ + π has the same shaded region but the boundary is presented by a dashed line. Thereβs just one step to solve this. Web the shaded region for the inequality is below the line. Web the shaded region shows the solution of the inequality \(y>2xβ1\). Every ordered pair in the shaded area below the line is a solution to y < 2x+5 y < 2 x + 5, as all of the points below the line will make the inequality true. In this case, we can see that the origin ( 0 , 0 ) β is a solution because it is in the shaded part, but the point ( 4 , 4 ) β is not a solution because it is outside of the shaded part.